0=2x^2+40x-3000

Solution for 0=2x^2+40x-3000 equation:

0=2x^2+40x-3000

We move all terms to the left:

0-(2x^2+40x-3000)=0

We add all the numbers together, and all the variables

-(2x^2+40x-3000)=0

We get rid of parentheses

-2x^2-40x+3000=0

a = -2; b = -40; c = +3000;
Δ = b2-4ac
Δ = -402-4·(-2)·3000
Δ = 25600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25600}=160$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-40)-160}{2*-2}=\frac{-120}{-4}
=+30
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-40)+160}{2*-2}=\frac{200}{-4}
=-50
$